WebI wrote a piece of code that returns a random string sponsorname from a list of sponsors. This sponsorname should be visible at each page, so I call the RandomSponsor method in the shared _layout view. This RandomSponsor method is based in the HomeController and has it's own view containing only a H WebAug 28, 2014 · public static List GetRandomNumbers (int count) { List randomNumbers = new List (); for (int i=0; i
C# 从列表中选择随机元素 - IT宝库
WebJan 30, 2013 · List list = new List () { "aaa", "bbb", "ccc", "ddd" }; int l = list.Count; Random r = new Random (); int num = r.Next (l); var randomStringFromList = list [num]; Also next time you should include the code that doesn't work along with (possible) reasons why. Share Improve this answer Follow edited Jan 30, 2013 at 0:07 WebMar 6, 2024 · We first initialized the list list1 and then shuffled the list list1 with the random.next() function and the OrderBy() function of Linq in C#. The above method can … jeep patriot sport suv
.net - Generating random, unique values C# - Stack Overflow
WebNov 12, 2011 · Random random = new Random (); List characters = new List () { }; You don't need the initialiser brackets when you don't put any items in the list at that point: List characters = new List (); result += characters [random.Next (0, characters.Count)]; Using += to concatenate strings is bad practice. http://james-ramsden.com/create-a-list-of-random-numbers-in-c/ WebI am trying to write an algorithm that would pick N distinct items from an sequence at random, without knowing the size of the sequence in advance, and where it is expensive to iterate over the sequence more than once.For example, the elements of the sequence might be the lines of a huge file. I have found a solution when N=1 (that is, "pick exactly one … jeep patriot suv 2012